Base | Representation |
---|---|
bin | 1010111011010101111000… |
… | …1000100010110110110010 |
3 | 1120112120210022212110222221 |
4 | 2232311132020202312302 |
5 | 3033321401310401023 |
6 | 41315233215151254 |
7 | 2350012025664514 |
oct | 256653610426662 |
9 | 46476708773887 |
10 | 12014602825138 |
11 | 3912401090531 |
12 | 142061621552a |
13 | 691c83b76214 |
14 | 2d771d175bb4 |
15 | 15c7d9e2d85d |
hex | aed5e222db2 |
12014602825138 has 32 divisors (see below), whose sum is σ = 18524275197120. Its totient is φ = 5840114719680.
The previous prime is 12014602825103. The next prime is 12014602825151. The reversal of 12014602825138 is 83152820641021.
It is a super-2 number, since 2×120146028251382 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 12014602825094 and 12014602825103.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 543414828 + ... + 543436936.
It is an arithmetic number, because the mean of its divisors is an integer number (578883599910).
Almost surely, 212014602825138 is an apocalyptic number.
12014602825138 is a deficient number, since it is larger than the sum of its proper divisors (6509672371982).
12014602825138 is a wasteful number, since it uses less digits than its factorization.
12014602825138 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 27882.
The product of its (nonzero) digits is 184320, while the sum is 43.
The spelling of 12014602825138 in words is "twelve trillion, fourteen billion, six hundred two million, eight hundred twenty-five thousand, one hundred thirty-eight".
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