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12014953 = 116310331
BaseRepresentation
bin101101110101…
…010101101001
3211121102102021
4231311111221
511033434303
61105304441
7204061006
oct55652551
924542367
1012014953
116867015
124035121
132648a52
14184a8ad
1510c4ebd
hexb75569

12014953 has 4 divisors (see below), whose sum is σ = 12026448. Its totient is φ = 12003460.

The previous prime is 12014929. The next prime is 12014957. The reversal of 12014953 is 35941021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 35941021 = 137326177.

It is a cyclic number.

It is not a de Polignac number, because 12014953 - 25 = 12014921 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12014957) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4003 + ... + 6328.

It is an arithmetic number, because the mean of its divisors is an integer number (3006612).

Almost surely, 212014953 is an apocalyptic number.

It is an amenable number.

12014953 is a deficient number, since it is larger than the sum of its proper divisors (11495).

12014953 is a wasteful number, since it uses less digits than its factorization.

12014953 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 11494.

The product of its (nonzero) digits is 1080, while the sum is 25.

The square root of 12014953 is about 3466.2592228511. The cubic root of 12014953 is about 229.0379029956.

Adding to 12014953 its reverse (35941021), we get a palindrome (47955974).

The spelling of 12014953 in words is "twelve million, fourteen thousand, nine hundred fifty-three".

Divisors: 1 1163 10331 12014953