Base | Representation |
---|---|
bin | 10110011000010011… |
… | …01011010101001001 |
3 | 1011000100101102121220 |
4 | 23030021223111021 |
5 | 144101321222213 |
6 | 5304123352253 |
7 | 603513004560 |
oct | 131411532511 |
9 | 34010342556 |
10 | 12015023433 |
11 | 5106192a36 |
12 | 23b3982689 |
13 | 11962c4a2a |
14 | 81da0cbd7 |
15 | 4a4c3be23 |
hex | 2cc26b549 |
12015023433 has 32 divisors (see below), whose sum is σ = 18495184896. Its totient is φ = 6795925248.
The previous prime is 12015023413. The next prime is 12015023441. The reversal of 12015023433 is 33432051021.
It is not a de Polignac number, because 12015023433 - 25 = 12015023401 is a prime.
It is not an unprimeable number, because it can be changed into a prime (12015023413) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 2044966 + ... + 2050832.
It is an arithmetic number, because the mean of its divisors is an integer number (577974528).
Almost surely, 212015023433 is an apocalyptic number.
It is an amenable number.
12015023433 is a deficient number, since it is larger than the sum of its proper divisors (6480161463).
12015023433 is a wasteful number, since it uses less digits than its factorization.
12015023433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6853.
The product of its (nonzero) digits is 2160, while the sum is 24.
Adding to 12015023433 its reverse (33432051021), we get a palindrome (45447074454).
The spelling of 12015023433 in words is "twelve billion, fifteen million, twenty-three thousand, four hundred thirty-three".
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