Base | Representation |
---|---|
bin | 1010111011010111100011… |
… | …0011101010010010111101 |
3 | 1120112121221111221100200212 |
4 | 2232311320303222102331 |
5 | 3033323310341213141 |
6 | 41315345443002205 |
7 | 2350026101524310 |
oct | 256657063522275 |
9 | 46477844840625 |
10 | 12015050335421 |
11 | 3912610756641 |
12 | 1420720069365 |
13 | 6920257b08c3 |
14 | 2d7762786977 |
15 | 15c8143792eb |
hex | aed78cea4bd |
12015050335421 has 32 divisors (see below), whose sum is σ = 14220337936896. Its totient is φ = 9938044800000.
The previous prime is 12015050335417. The next prime is 12015050335451. The reversal of 12015050335421 is 12453305051021.
It is a cyclic number.
It is not a de Polignac number, because 12015050335421 - 22 = 12015050335417 is a prime.
It is a super-2 number, since 2×120150503354212 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12015050335451) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 9502571 + ... + 10692471.
It is an arithmetic number, because the mean of its divisors is an integer number (444385560528).
Almost surely, 212015050335421 is an apocalyptic number.
It is an amenable number.
12015050335421 is a deficient number, since it is larger than the sum of its proper divisors (2205287601475).
12015050335421 is a wasteful number, since it uses less digits than its factorization.
12015050335421 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1190333.
The product of its (nonzero) digits is 18000, while the sum is 32.
Adding to 12015050335421 its reverse (12453305051021), we get a palindrome (24468355386442).
The spelling of 12015050335421 in words is "twelve trillion, fifteen billion, fifty million, three hundred thirty-five thousand, four hundred twenty-one".
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