Base | Representation |
---|---|
bin | 1010111011011000001000… |
… | …0001110110101010101011 |
3 | 1120112122100022001201122101 |
4 | 2232312002001312222223 |
5 | 3033324114443113201 |
6 | 41315413051034231 |
7 | 2350032660554266 |
oct | 256660201665253 |
9 | 46478308051571 |
10 | 12015205051051 |
11 | 39126900197a4 |
12 | 1420763a3b977 |
13 | 69204b871007 |
14 | 2d777913bcdd |
15 | 15c822c3ad01 |
hex | aed82076aab |
12015205051051 has 2 divisors, whose sum is σ = 12015205051052. Its totient is φ = 12015205051050.
The previous prime is 12015205051033. The next prime is 12015205051061. The reversal of 12015205051051 is 15015050251021.
12015205051051 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12015205051051 - 27 = 12015205050923 is a prime.
It is not a weakly prime, because it can be changed into another prime (12015205051021) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6007602525525 + 6007602525526.
It is an arithmetic number, because the mean of its divisors is an integer number (6007602525526).
Almost surely, 212015205051051 is an apocalyptic number.
12015205051051 is a deficient number, since it is larger than the sum of its proper divisors (1).
12015205051051 is an equidigital number, since it uses as much as digits as its factorization.
12015205051051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2500, while the sum is 28.
The spelling of 12015205051051 in words is "twelve trillion, fifteen billion, two hundred five million, fifty-one thousand, fifty-one".
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