12015340524323 has 4 divisors (see below), whose sum is σ = 12016684380768. Its totient is φ = 12013996667880.

The previous prime is 12015340524307. The next prime is 12015340524403. The reversal of 12015340524323 is 32342504351021.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 12015340524323 - 2⁴ = 12015340524307 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12015340524023) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 671914811 + ... + 671932692.

It is an arithmetic number, because the mean of its divisors is an integer number (3004171095192).

Almost surely, 2^{12015340524323} is an apocalyptic number.

12015340524323 is a deficient number, since it is larger than the sum of its proper divisors (1343856445).

12015340524323 is an equidigital number, since it uses as much as digits as its factorization.

12015340524323 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1343856444.

The product of its (nonzero) digits is 86400, while the sum is 35.

Adding to 12015340524323 its reverse (32342504351021), we get a palindrome (44357844875344).

The spelling of 12015340524323 in words is "twelve trillion, fifteen billion, three hundred forty million, five hundred twenty-four thousand, three hundred twenty-three".