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12016205264433 = 38945004514099
BaseRepresentation
bin1010111011011011110110…
…1001010111011000110001
31120112201221000010211110110
42232312331221113120301
53033333142021430213
641320100221051533
72350066524334266
oct256667551273061
946481830124413
1012016205264433
113913053678927
1214209a29b6ba9
1369217ab54356
142d7831d0326d
1515c8809605c3
hexaedbda57631

12016205264433 has 8 divisors (see below), whose sum is σ = 16201625076000. Its totient is φ = 7920794481248.

The previous prime is 12016205264419. The next prime is 12016205264501. The reversal of 12016205264433 is 33446250261021.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 12016205264433 - 26 = 12016205264369 is a prime.

It is a super-2 number, since 2×120162052644332 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 12016205264391 and 12016205264400.

It is not an unprimeable number, because it can be changed into a prime (12016205264033) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 22502256783 + ... + 22502257316.

It is an arithmetic number, because the mean of its divisors is an integer number (2025203134500).

Almost surely, 212016205264433 is an apocalyptic number.

It is an amenable number.

12016205264433 is a deficient number, since it is larger than the sum of its proper divisors (4185419811567).

12016205264433 is an equidigital number, since it uses as much as digits as its factorization.

12016205264433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 45004514191.

The product of its (nonzero) digits is 207360, while the sum is 39.

The spelling of 12016205264433 in words is "twelve trillion, sixteen billion, two hundred five million, two hundred sixty-four thousand, four hundred thirty-three".

Divisors: 1 3 89 267 45004514099 135013542297 4005401754811 12016205264433