Base | Representation |
---|---|
bin | 1010111011100011111100… |
… | …0101011111101100101011 |
3 | 1120112221112100110022120002 |
4 | 2232320333011133230223 |
5 | 3033402113441234441 |
6 | 41321055514453215 |
7 | 2350204404044423 |
oct | 256707705375453 |
9 | 46487470408502 |
10 | 12018376899371 |
11 | 3913a68494347 |
12 | 14212aa13420b |
13 | 692435a33c3b |
14 | 2d799a4b9483 |
15 | 15c95b427b9b |
hex | aee3f15fb2b |
12018376899371 has 2 divisors, whose sum is σ = 12018376899372. Its totient is φ = 12018376899370.
The previous prime is 12018376899283. The next prime is 12018376899383. The reversal of 12018376899371 is 17399867381021.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12018376899371 - 210 = 12018376898347 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 12018376899298 and 12018376899307.
It is not a weakly prime, because it can be changed into another prime (12018376899071) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6009188449685 + 6009188449686.
It is an arithmetic number, because the mean of its divisors is an integer number (6009188449686).
Almost surely, 212018376899371 is an apocalyptic number.
12018376899371 is a deficient number, since it is larger than the sum of its proper divisors (1).
12018376899371 is an equidigital number, since it uses as much as digits as its factorization.
12018376899371 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 27433728, while the sum is 65.
The spelling of 12018376899371 in words is "twelve trillion, eighteen billion, three hundred seventy-six million, eight hundred ninety-nine thousand, three hundred seventy-one".
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