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120202004131 = 11269311130619
BaseRepresentation
bin110111111110010011…
…0010000011010100011
3102111021002021111001221
41233330212100122203
53432133203113011
6131115310035511
711453501114506
oct1577446203243
9374232244057
10120202004131
1146a82996890
121b3674a8b97
13b447cc3941
145b640cb13d
1531d7aa8971
hex1bfc9906a3

120202004131 has 16 divisors (see below), whose sum is σ = 132041145600. Its totient is φ = 108517434400.

The previous prime is 120202004119. The next prime is 120202004137. The reversal of 120202004131 is 131400202021.

It is a cyclic number.

It is not a de Polignac number, because 120202004131 - 217 = 120201873059 is a prime.

It is a super-3 number, since 3×1202020041313 (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not an unprimeable number, because it can be changed into a prime (120202004137) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 854940 + ... + 985558.

It is an arithmetic number, because the mean of its divisors is an integer number (8252571600).

Almost surely, 2120202004131 is an apocalyptic number.

120202004131 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

120202004131 is a deficient number, since it is larger than the sum of its proper divisors (11839141469).

120202004131 is a wasteful number, since it uses less digits than its factorization.

120202004131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 131210.

The product of its (nonzero) digits is 96, while the sum is 16.

Adding to 120202004131 its reverse (131400202021), we get a palindrome (251602206152).

The spelling of 120202004131 in words is "one hundred twenty billion, two hundred two million, four thousand, one hundred thirty-one".

Divisors: 1 11 269 311 2959 3421 83659 130619 920249 1436809 35136511 40622509 386501621 446847599 10927454921 120202004131