Base | Representation |
---|---|
bin | 10110011000111011… |
… | …10100011001001001 |
3 | 1011000201022200102110 |
4 | 23030131310121021 |
5 | 144104144202213 |
6 | 5304432452533 |
7 | 603605615265 |
oct | 131435643111 |
9 | 34021280373 |
10 | 12020303433 |
11 | 5109169976 |
12 | 23b56aa149 |
13 | 11974230a8 |
14 | 8205c50a5 |
15 | 4a54315c3 |
hex | 2cc774649 |
12020303433 has 16 divisors (see below), whose sum is σ = 16066918080. Its totient is φ = 7993637184.
The previous prime is 12020303429. The next prime is 12020303473. The reversal of 12020303433 is 33430302021.
12020303433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 12020303433 - 22 = 12020303429 is a prime.
It is not an unprimeable number, because it can be changed into a prime (12020303473) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2993335 + ... + 2997347.
It is an arithmetic number, because the mean of its divisors is an integer number (1004182380).
Almost surely, 212020303433 is an apocalyptic number.
It is an amenable number.
12020303433 is a deficient number, since it is larger than the sum of its proper divisors (4046614647).
12020303433 is a wasteful number, since it uses less digits than its factorization.
12020303433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6248.
The product of its (nonzero) digits is 1296, while the sum is 21.
Adding to 12020303433 its reverse (33430302021), we get a palindrome (45450605454).
The spelling of 12020303433 in words is "twelve billion, twenty million, three hundred three thousand, four hundred thirty-three".
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