Base | Representation |
---|---|
bin | 1010111011101011001001… |
… | …1011110100100110101011 |
3 | 1120120010112012221022200001 |
4 | 2232322302123310212223 |
5 | 3033420044401211021 |
6 | 41322015525323431 |
7 | 2350303353205201 |
oct | 256726233644653 |
9 | 46503465838601 |
10 | 12020312132011 |
11 | 3914870914267 |
12 | 142174a266577 |
13 | 692683952401 |
14 | 2d7b01515071 |
15 | 15ca21295091 |
hex | aeeb26f49ab |
12020312132011 has 2 divisors, whose sum is σ = 12020312132012. Its totient is φ = 12020312132010.
The previous prime is 12020312131963. The next prime is 12020312132141. The reversal of 12020312132011 is 11023121302021.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12020312132011 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 12020312132011.
It is not a weakly prime, because it can be changed into another prime (12020312132911) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6010156066005 + 6010156066006.
It is an arithmetic number, because the mean of its divisors is an integer number (6010156066006).
Almost surely, 212020312132011 is an apocalyptic number.
12020312132011 is a deficient number, since it is larger than the sum of its proper divisors (1).
12020312132011 is an equidigital number, since it uses as much as digits as its factorization.
12020312132011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 12020312132011 its reverse (11023121302021), we get a palindrome (23043433434032).
The spelling of 12020312132011 in words is "twelve trillion, twenty billion, three hundred twelve million, one hundred thirty-two thousand, eleven".
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