Base | Representation |
---|---|
bin | 1010111011101011001110… |
… | …0001010000000010101010 |
3 | 1120120010120111011222210221 |
4 | 2232322303201100002222 |
5 | 3033420114031113310 |
6 | 41322021415400254 |
7 | 2350303664000305 |
oct | 256726341200252 |
9 | 46503514158727 |
10 | 12020330332330 |
11 | 3914880115451 |
12 | 142175438308a |
13 | 692687655628 |
14 | 2d7b03ad1b3c |
15 | 15ca22b8cada |
hex | aeeb38500aa |
12020330332330 has 16 divisors (see below), whose sum is σ = 21636974226600. Its totient is φ = 4808047771072.
The previous prime is 12020330332319. The next prime is 12020330332357. The reversal of 12020330332330 is 3323303302021.
It can be written as a sum of positive squares in 4 ways, for example, as 3933649455649 + 8086680876681 = 1983343^2 + 2843709^2 .
It is a junction number, because it is equal to n+sod(n) for n = 12020330332295 and 12020330332304.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 9945169 + ... + 11088148.
Almost surely, 212020330332330 is an apocalyptic number.
12020330332330 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
12020330332330 is a deficient number, since it is larger than the sum of its proper divisors (9616643894270).
12020330332330 is a wasteful number, since it uses less digits than its factorization.
12020330332330 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 21090473.
The product of its (nonzero) digits is 5832, while the sum is 25.
Adding to 12020330332330 its reverse (3323303302021), we get a palindrome (15343633634351).
The spelling of 12020330332330 in words is "twelve trillion, twenty billion, three hundred thirty million, three hundred thirty-two thousand, three hundred thirty".
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