Base | Representation |
---|---|
bin | 1010111011101011110111… |
… | …0111110000100110110001 |
3 | 1120120011000120222110222120 |
4 | 2232322331313300212301 |
5 | 3033420443011130131 |
6 | 41322050542024453 |
7 | 2350311203123610 |
oct | 256727567604661 |
9 | 46504016873876 |
10 | 12020504005041 |
11 | 391495a156314 |
12 | 14217a2578129 |
13 | 6926b462254c |
14 | 2d7b1cbbd877 |
15 | 15ca33046496 |
hex | aeebddf09b1 |
12020504005041 has 32 divisors (see below), whose sum is σ = 18908122914816. Its totient is φ = 6647179680000.
The previous prime is 12020504005031. The next prime is 12020504005057. The reversal of 12020504005041 is 14050040502021.
It is not a de Polignac number, because 12020504005041 - 217 = 12020503873969 is a prime.
It is not an unprimeable number, because it can be changed into a prime (12020504005001) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 62693881 + ... + 62885321.
It is an arithmetic number, because the mean of its divisors is an integer number (590878841088).
Almost surely, 212020504005041 is an apocalyptic number.
It is an amenable number.
12020504005041 is a deficient number, since it is larger than the sum of its proper divisors (6887618909775).
12020504005041 is a wasteful number, since it uses less digits than its factorization.
12020504005041 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 287933.
The product of its (nonzero) digits is 1600, while the sum is 24.
Adding to 12020504005041 its reverse (14050040502021), we get a palindrome (26070544507062).
The spelling of 12020504005041 in words is "twelve trillion, twenty billion, five hundred four million, five thousand, forty-one".
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