12020504005031 has 2 divisors, whose sum is σ = 12020504005032. Its totient is φ = 12020504005030.

The previous prime is 12020504005021. The next prime is 12020504005057. The reversal of 12020504005031 is 13050040502021.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-12020504005031 is a prime.

It is a super-2 number, since 2×12020504005031² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 12020504004988 and 12020504005006.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12020504005001) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6010252002515 + 6010252002516.

It is an arithmetic number, because the mean of its divisors is an integer number (6010252002516).

Almost surely, 2^{12020504005031} is an apocalyptic number.

12020504005031 is a deficient number, since it is larger than the sum of its proper divisors (1).

12020504005031 is an equidigital number, since it uses as much as digits as its factorization.

12020504005031 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1200, while the sum is 23.

Adding to 12020504005031 its reverse (13050040502021), we get a palindrome (25070544507052).

The spelling of 12020504005031 in words is "twelve trillion, twenty billion, five hundred four million, five thousand, thirty-one".