Base | Representation |
---|---|
bin | 10001011111100000000… |
… | …111110100100001111001 |
3 | 11020220201100110212010111 |
4 | 101133200013310201321 |
5 | 124143302320202022 |
6 | 2320114504144321 |
7 | 152563032413455 |
oct | 21374007644171 |
9 | 4226640425114 |
10 | 1202056022137 |
11 | 423875317a43 |
12 | 174b721680a1 |
13 | 89479548559 |
14 | 42273607665 |
15 | 21405467477 |
hex | 117e01f4879 |
1202056022137 has 2 divisors, whose sum is σ = 1202056022138. Its totient is φ = 1202056022136.
The previous prime is 1202056022131. The next prime is 1202056022147. The reversal of 1202056022137 is 7312206502021.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 613001307136 + 589054715001 = 782944^2 + 767499^2 .
It is a cyclic number.
It is not a de Polignac number, because 1202056022137 - 23 = 1202056022129 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1202056022099 and 1202056022108.
It is not a weakly prime, because it can be changed into another prime (1202056022131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 601028011068 + 601028011069.
It is an arithmetic number, because the mean of its divisors is an integer number (601028011069).
Almost surely, 21202056022137 is an apocalyptic number.
It is an amenable number.
1202056022137 is a deficient number, since it is larger than the sum of its proper divisors (1).
1202056022137 is an equidigital number, since it uses as much as digits as its factorization.
1202056022137 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10080, while the sum is 31.
The spelling of 1202056022137 in words is "one trillion, two hundred two billion, fifty-six million, twenty-two thousand, one hundred thirty-seven".
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