Base | Representation |
---|---|
bin | 110111111110100010… |
… | …1001011011001100011 |
3 | 102111021122112022022012 |
4 | 1233331011023121203 |
5 | 3432142242010201 |
6 | 131120155503135 |
7 | 11453630035103 |
oct | 1577505133143 |
9 | 374248468265 |
10 | 120210110051 |
11 | 46a87522999 |
12 | 1b36a157aab |
13 | b4498a1345 |
14 | 5b651db203 |
15 | 31d865a5bb |
hex | 1bfd14b663 |
120210110051 has 2 divisors, whose sum is σ = 120210110052. Its totient is φ = 120210110050.
The previous prime is 120210110047. The next prime is 120210110089. The reversal of 120210110051 is 150011012021.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 120210110051 - 22 = 120210110047 is a prime.
It is not a weakly prime, because it can be changed into another prime (120210116051) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60105055025 + 60105055026.
It is an arithmetic number, because the mean of its divisors is an integer number (60105055026).
Almost surely, 2120210110051 is an apocalyptic number.
120210110051 is a deficient number, since it is larger than the sum of its proper divisors (1).
120210110051 is an equidigital number, since it uses as much as digits as its factorization.
120210110051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 20, while the sum is 14.
Adding to 120210110051 its reverse (150011012021), we get a palindrome (270221122072).
The spelling of 120210110051 in words is "one hundred twenty billion, two hundred ten million, one hundred ten thousand, fifty-one".
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