12021101012017 has 2 divisors, whose sum is σ = 12021101012018. Its totient is φ = 12021101012016.

The previous prime is 12021101012009. The next prime is 12021101012029. The reversal of 12021101012017 is 71021010112021.

12021101012017 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11524232509696 + 496868502321 = 3394736^2 + 704889^2 .

It is an emirp because it is prime and its reverse (71021010112021) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 12021101012017 - 2³ = 12021101012009 is a prime.

It is a super-2 number, since 2×12021101012017² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 12021101011985 and 12021101012003.

It is not a weakly prime, because it can be changed into another prime (12021101012077) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6010550506008 + 6010550506009.

It is an arithmetic number, because the mean of its divisors is an integer number (6010550506009).

Almost surely, 2^{12021101012017} is an apocalyptic number.

It is an amenable number.

12021101012017 is a deficient number, since it is larger than the sum of its proper divisors (1).

12021101012017 is an equidigital number, since it uses as much as digits as its factorization.

12021101012017 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 56, while the sum is 19.

Adding to 12021101012017 its reverse (71021010112021), we get a palindrome (83042111124038).

The spelling of 12021101012017 in words is "twelve trillion, twenty-one billion, one hundred one million, twelve thousand, seventeen".