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12021103220131 is a prime number
BaseRepresentation
bin1010111011101110000110…
…0101100101010110100011
31120120012120100111202120001
42232323201211211112203
53033423204411021011
641322230225200431
72350332100303435
oct256734145452643
946505510452501
1012021103220131
1139151374184a5
12142192b190117
1369277b804aa5
142d7b78600655
1515ca6a95b7c1
hexaeee19655a3

12021103220131 has 2 divisors, whose sum is σ = 12021103220132. Its totient is φ = 12021103220130.

The previous prime is 12021103220117. The next prime is 12021103220143. The reversal of 12021103220131 is 13102230112021.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 12021103220131 - 27 = 12021103220003 is a prime.

It is a super-2 number, since 2×120211032201312 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 12021103220099 and 12021103220108.

It is not a weakly prime, because it can be changed into another prime (12021103220431) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6010551610065 + 6010551610066.

It is an arithmetic number, because the mean of its divisors is an integer number (6010551610066).

Almost surely, 212021103220131 is an apocalyptic number.

12021103220131 is a deficient number, since it is larger than the sum of its proper divisors (1).

12021103220131 is an equidigital number, since it uses as much as digits as its factorization.

12021103220131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 12021103220131 its reverse (13102230112021), we get a palindrome (25123333332152).

The spelling of 12021103220131 in words is "twelve trillion, twenty-one billion, one hundred three million, two hundred twenty thousand, one hundred thirty-one".