Base | Representation |
---|---|
bin | 11011010101010011011010… |
… | …100010010001111100111011 |
3 | 120202122002010222201121101102 |
4 | 123111103122202101330323 |
5 | 111224020030020144323 |
6 | 1103400133515442015 |
7 | 34214654606001614 |
oct | 3325233242217473 |
9 | 522562128647342 |
10 | 120211211099963 |
11 | 35337319847785 |
12 | 115958a345630b |
13 | 520cb3a315bb9 |
14 | 219837a092c0b |
15 | dd6e81e67328 |
hex | 6d54da891f3b |
120211211099963 has 2 divisors, whose sum is σ = 120211211099964. Its totient is φ = 120211211099962.
The previous prime is 120211211099923. The next prime is 120211211100053. The reversal of 120211211099963 is 369990112112021.
It is a weak prime.
It is an emirp because it is prime and its reverse (369990112112021) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 120211211099963 - 242 = 115813164588859 is a prime.
It is not a weakly prime, because it can be changed into another prime (120211211099923) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60105605549981 + 60105605549982.
It is an arithmetic number, because the mean of its divisors is an integer number (60105605549982).
Almost surely, 2120211211099963 is an apocalyptic number.
120211211099963 is a deficient number, since it is larger than the sum of its proper divisors (1).
120211211099963 is an equidigital number, since it uses as much as digits as its factorization.
120211211099963 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 104976, while the sum is 47.
The spelling of 120211211099963 in words is "one hundred twenty trillion, two hundred eleven billion, two hundred eleven million, ninety-nine thousand, nine hundred sixty-three".
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