Base | Representation |
---|---|
bin | 110111111110100100… |
… | …1100010100011000011 |
3 | 102111021201200101202001 |
4 | 1233331021202203003 |
5 | 3432143040102233 |
6 | 131120240204431 |
7 | 11453642536441 |
oct | 1577511424303 |
9 | 374251611661 |
10 | 120211253443 |
11 | 46a88133a46 |
12 | 1b36a609717 |
13 | b449bb18c8 |
14 | 5b65417b91 |
15 | 31d87d427d |
hex | 1bfd2628c3 |
120211253443 has 4 divisors (see below), whose sum is σ = 120212505288. Its totient is φ = 120210001600.
The previous prime is 120211253423. The next prime is 120211253467. The reversal of 120211253443 is 344352112021.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 344352112021 = 4793 ⋅71844797.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-120211253443 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (120211253423) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 468721 + ... + 678322.
It is an arithmetic number, because the mean of its divisors is an integer number (30053126322).
Almost surely, 2120211253443 is an apocalyptic number.
120211253443 is a deficient number, since it is larger than the sum of its proper divisors (1251845).
120211253443 is a wasteful number, since it uses less digits than its factorization.
120211253443 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1251844.
The product of its (nonzero) digits is 5760, while the sum is 28.
Adding to 120211253443 its reverse (344352112021), we get a palindrome (464563365464).
The spelling of 120211253443 in words is "one hundred twenty billion, two hundred eleven million, two hundred fifty-three thousand, four hundred forty-three".
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