Base | Representation |
---|---|
bin | 1010111011101110100101… |
… | …0000110101110000000011 |
3 | 1120120012220022211110022221 |
4 | 2232323221100311300003 |
5 | 3033423440343000003 |
6 | 41322251105311511 |
7 | 2350335223023112 |
oct | 256735120656003 |
9 | 46505808743287 |
10 | 12021232000003 |
11 | 39151a3086746 |
12 | 1421966335597 |
13 | 69279c3b40b5 |
14 | 2d7b8b763c79 |
15 | 15ca76de87bd |
hex | aeee9435c03 |
12021232000003 has 2 divisors, whose sum is σ = 12021232000004. Its totient is φ = 12021232000002.
The previous prime is 12021231999983. The next prime is 12021232000013. The reversal of 12021232000003 is 30000023212021.
12021232000003 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12021232000003 is a prime.
It is a super-2 number, since 2×120212320000032 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (12021232000013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6010616000001 + 6010616000002.
It is an arithmetic number, because the mean of its divisors is an integer number (6010616000002).
Almost surely, 212021232000003 is an apocalyptic number.
12021232000003 is a deficient number, since it is larger than the sum of its proper divisors (1).
12021232000003 is an equidigital number, since it uses as much as digits as its factorization.
12021232000003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144, while the sum is 16.
Adding to 12021232000003 its reverse (30000023212021), we get a palindrome (42021255212024).
The spelling of 12021232000003 in words is "twelve trillion, twenty-one billion, two hundred thirty-two million, three", and thus it is an aban number.
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