Base | Representation |
---|---|
bin | 110111111110101000… |
… | …1011001000011101011 |
3 | 102111021212112222011122 |
4 | 1233331101121003223 |
5 | 3432144101433343 |
6 | 131120352245455 |
7 | 11453666201321 |
oct | 1577521310353 |
9 | 374255488148 |
10 | 120213311723 |
11 | 46a8930a3aa |
12 | 1b36b24088b |
13 | b44a45271b |
14 | 5b657d1d11 |
15 | 31d8a8e068 |
hex | 1bfd4590eb |
120213311723 has 2 divisors, whose sum is σ = 120213311724. Its totient is φ = 120213311722.
The previous prime is 120213311689. The next prime is 120213311731. The reversal of 120213311723 is 327113312021.
It is a strong prime.
It is an emirp because it is prime and its reverse (327113312021) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 120213311723 - 222 = 120209117419 is a prime.
It is a super-2 number, since 2×1202133117232 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 120213311692 and 120213311701.
It is not a weakly prime, because it can be changed into another prime (120213317723) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60106655861 + 60106655862.
It is an arithmetic number, because the mean of its divisors is an integer number (60106655862).
Almost surely, 2120213311723 is an apocalyptic number.
120213311723 is a deficient number, since it is larger than the sum of its proper divisors (1).
120213311723 is an equidigital number, since it uses as much as digits as its factorization.
120213311723 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1512, while the sum is 26.
Adding to 120213311723 its reverse (327113312021), we get a palindrome (447326623744).
The spelling of 120213311723 in words is "one hundred twenty billion, two hundred thirteen million, three hundred eleven thousand, seven hundred twenty-three".
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