12021435032017 has 2 divisors, whose sum is σ = 12021435032018. Its totient is φ = 12021435032016.

The previous prime is 12021435031999. The next prime is 12021435032053. The reversal of 12021435032017 is 71023053412021.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12018154491841 + 3280540176 = 3466721^2 + 57276^2 .

It is an emirp because it is prime and its reverse (71023053412021) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-12021435032017 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 12021435032017.

It is not a weakly prime, because it can be changed into another prime (12021445032017) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6010717516008 + 6010717516009.

It is an arithmetic number, because the mean of its divisors is an integer number (6010717516009).

Almost surely, 2^{12021435032017} is an apocalyptic number.

It is an amenable number.

12021435032017 is a deficient number, since it is larger than the sum of its proper divisors (1).

12021435032017 is an equidigital number, since it uses as much as digits as its factorization.

12021435032017 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 10080, while the sum is 31.

Adding to 12021435032017 its reverse (71023053412021), we get a palindrome (83044488444038).

The spelling of 12021435032017 in words is "twelve trillion, twenty-one billion, four hundred thirty-five million, thirty-two thousand, seventeen".