12021441433 has 4 divisors (see below), whose sum is σ = 12200866000. Its totient is φ = 11842016868.

The previous prime is 12021441409. The next prime is 12021441529. The reversal of 12021441433 is 33414412021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 33414412021 = 140177 ⋅238373.

It is a cyclic number.

It is not a de Polignac number, because 12021441433 - 2¹⁷ = 12021310361 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12021441398 and 12021441407.

It is not an unprimeable number, because it can be changed into a prime (12022441433) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 89712183 + ... + 89712316.

It is an arithmetic number, because the mean of its divisors is an integer number (3050216500).

Almost surely, 2^12021441433 is an apocalyptic number.

It is an amenable number.

12021441433 is a deficient number, since it is larger than the sum of its proper divisors (179424567).

12021441433 is an equidigital number, since it uses as much as digits as its factorization.

12021441433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 179424566.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 12021441433 its reverse (33414412021), we get a palindrome (45435853454).

The spelling of 12021441433 in words is "twelve billion, twenty-one million, four hundred forty-one thousand, four hundred thirty-three".