Base | Representation |
---|---|
bin | 110111111110110101… |
… | …0111010001101111011 |
3 | 102111022100010211100002 |
4 | 1233331222322031323 |
5 | 3432202310014042 |
6 | 131121151503215 |
7 | 11454110102111 |
oct | 1577552721573 |
9 | 374270124302 |
10 | 120220001147 |
11 | 46a92069254 |
12 | 1b371527b0b |
13 | b44b95546c |
14 | 5b66653ab1 |
15 | 31d9461132 |
hex | 1bfdaba37b |
120220001147 has 2 divisors, whose sum is σ = 120220001148. Its totient is φ = 120220001146.
The previous prime is 120220001119. The next prime is 120220001171. The reversal of 120220001147 is 741100022021.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 120220001147 - 220 = 120218952571 is a prime.
It is not a weakly prime, because it can be changed into another prime (120220001197) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60110000573 + 60110000574.
It is an arithmetic number, because the mean of its divisors is an integer number (60110000574).
Almost surely, 2120220001147 is an apocalyptic number.
120220001147 is a deficient number, since it is larger than the sum of its proper divisors (1).
120220001147 is an equidigital number, since it uses as much as digits as its factorization.
120220001147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 224, while the sum is 20.
Adding to 120220001147 its reverse (741100022021), we get a palindrome (861320023168).
The spelling of 120220001147 in words is "one hundred twenty billion, two hundred twenty million, one thousand, one hundred forty-seven".
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