Base | Representation |
---|---|
bin | 11011010101011011100110… |
… | …111111010011001011100001 |
3 | 120202122220212012100102200212 |
4 | 123111123212333103023201 |
5 | 111224141040022441403 |
6 | 1103404150554023505 |
7 | 34215415630103261 |
oct | 3325334677231341 |
9 | 522586765312625 |
10 | 120220009968353 |
11 | 35340024552839 |
12 | 1159753a117b95 |
13 | 5210910203ab9 |
14 | 21989728ad7a1 |
15 | dd72e96644d8 |
hex | 6d56e6fd32e1 |
120220009968353 has 2 divisors, whose sum is σ = 120220009968354. Its totient is φ = 120220009968352.
The previous prime is 120220009968343. The next prime is 120220009968407. The reversal of 120220009968353 is 353869900022021.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 120185351816464 + 34658151889 = 10962908^2 + 186167^2 .
It is a cyclic number.
It is not a de Polignac number, because 120220009968353 - 210 = 120220009967329 is a prime.
It is not a weakly prime, because it can be changed into another prime (120220009968343) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60110004984176 + 60110004984177.
It is an arithmetic number, because the mean of its divisors is an integer number (60110004984177).
Almost surely, 2120220009968353 is an apocalyptic number.
It is an amenable number.
120220009968353 is a deficient number, since it is larger than the sum of its proper divisors (1).
120220009968353 is an equidigital number, since it uses as much as digits as its factorization.
120220009968353 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1399680, while the sum is 50.
The spelling of 120220009968353 in words is "one hundred twenty trillion, two hundred twenty billion, nine million, nine hundred sixty-eight thousand, three hundred fifty-three".
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