Base | Representation |
---|---|
bin | 1010111011110001011111… |
… | …0001011100101101110011 |
3 | 1120120021220201002210220021 |
4 | 2232330113301130231303 |
5 | 3033432040122101042 |
6 | 41322500342024311 |
7 | 2350363446330463 |
oct | 256742761345563 |
9 | 46507821083807 |
10 | 12022012300147 |
11 | 39155635917a3 |
12 | 1421b43718097 |
13 | 692894c5a365 |
14 | 2d7c23241ba3 |
15 | 15cac067d867 |
hex | aef17c5cb73 |
12022012300147 has 2 divisors, whose sum is σ = 12022012300148. Its totient is φ = 12022012300146.
The previous prime is 12022012300117. The next prime is 12022012300211. The reversal of 12022012300147 is 74100321022021.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12022012300147 - 27 = 12022012300019 is a prime.
It is not a weakly prime, because it can be changed into another prime (12022012300117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6011006150073 + 6011006150074.
It is an arithmetic number, because the mean of its divisors is an integer number (6011006150074).
Almost surely, 212022012300147 is an apocalyptic number.
12022012300147 is a deficient number, since it is larger than the sum of its proper divisors (1).
12022012300147 is an equidigital number, since it uses as much as digits as its factorization.
12022012300147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1344, while the sum is 25.
Adding to 12022012300147 its reverse (74100321022021), we get a palindrome (86122333322168).
The spelling of 12022012300147 in words is "twelve trillion, twenty-two billion, twelve million, three hundred thousand, one hundred forty-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.117 sec. • engine limits •