Base | Representation |
---|---|
bin | 10001011111101000110… |
… | …101000110100001011001 |
3 | 11020221002112100220001121 |
4 | 101133220311012201121 |
5 | 124144102220010131 |
6 | 2320141203245241 |
7 | 152566455220642 |
oct | 21375065064131 |
9 | 4227075326047 |
10 | 1202202110041 |
11 | 42393a827a49 |
12 | 174bb3079821 |
13 | 894a08a78ba |
14 | 42288b946c9 |
15 | 214131c2911 |
hex | 117e8d46859 |
1202202110041 has 2 divisors, whose sum is σ = 1202202110042. Its totient is φ = 1202202110040.
The previous prime is 1202202110033. The next prime is 1202202110059. The reversal of 1202202110041 is 1400112022021.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 708795610000 + 493406500041 = 841900^2 + 702429^2 .
It is a cyclic number.
It is not a de Polignac number, because 1202202110041 - 23 = 1202202110033 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1202202109997 and 1202202110024.
It is not a weakly prime, because it can be changed into another prime (1202202110441) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 601101055020 + 601101055021.
It is an arithmetic number, because the mean of its divisors is an integer number (601101055021).
Almost surely, 21202202110041 is an apocalyptic number.
It is an amenable number.
1202202110041 is a deficient number, since it is larger than the sum of its proper divisors (1).
1202202110041 is an equidigital number, since it uses as much as digits as its factorization.
1202202110041 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 64, while the sum is 16.
Adding to 1202202110041 its reverse (1400112022021), we get a palindrome (2602314132062).
The spelling of 1202202110041 in words is "one trillion, two hundred two billion, two hundred two million, one hundred ten thousand, forty-one".
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