Base | Representation |
---|---|
bin | 11011010101011011110011… |
… | …100100010100110110111011 |
3 | 120202122221101220110000021021 |
4 | 123111123303210110312323 |
5 | 111224142003034014042 |
6 | 1103404223533123311 |
7 | 34215424101621241 |
oct | 3325336344246673 |
9 | 522587356400237 |
10 | 120220221001147 |
11 | 35340122690903 |
12 | 11597598929537 |
13 | 5210944b51a87 |
14 | 2198992924791 |
15 | dd730ce4c867 |
hex | 6d56f3914dbb |
120220221001147 has 2 divisors, whose sum is σ = 120220221001148. Its totient is φ = 120220221001146.
The previous prime is 120220221001051. The next prime is 120220221001163. The reversal of 120220221001147 is 741100122022021.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-120220221001147 is a prime.
It is not a weakly prime, because it can be changed into another prime (120220221007147) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60110110500573 + 60110110500574.
It is an arithmetic number, because the mean of its divisors is an integer number (60110110500574).
Almost surely, 2120220221001147 is an apocalyptic number.
120220221001147 is a deficient number, since it is larger than the sum of its proper divisors (1).
120220221001147 is an equidigital number, since it uses as much as digits as its factorization.
120220221001147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 896, while the sum is 25.
Adding to 120220221001147 its reverse (741100122022021), we get a palindrome (861320343023168).
The spelling of 120220221001147 in words is "one hundred twenty trillion, two hundred twenty billion, two hundred twenty-one million, one thousand, one hundred forty-seven".
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