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12022103001132 = 223372343473131093
BaseRepresentation
bin1010111011110001110100…
…1011011100100000101100
31120120022011000202220021000
42232330131023130200230
53033432231332014012
641322513342040300
72350365630303030
oct256743513344054
946508130686230
1012022103001132
1139155aa801794
121421b69b79090
136928aa996393
142d7c312d21c0
1515cac85e7ddc
hexaef1d2dc82c

12022103001132 has 768 divisors, whose sum is σ = 39003191377920. Its totient is φ = 3127957088256.

The previous prime is 12022103001119. The next prime is 12022103001149. The reversal of 12022103001132 is 23110030122021.

12022103001132 is a `hidden beast` number, since 1 + 20 + 2 + 210 + 300 + 1 + 132 = 666.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 255 ways as a sum of consecutive naturals, for example, 10999178778 + ... + 10999179870.

It is an arithmetic number, because the mean of its divisors is an integer number (50785405440).

Almost surely, 212022103001132 is an apocalyptic number.

12022103001132 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 12022103001132, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (19501595688960).

12022103001132 is an abundant number, since it is smaller than the sum of its proper divisors (26981088376788).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

12022103001132 is a wasteful number, since it uses less digits than its factorization.

12022103001132 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1539 (or 1531 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 18.

Adding to 12022103001132 its reverse (23110030122021), we get a palindrome (35132133123153).

The spelling of 12022103001132 in words is "twelve trillion, twenty-two billion, one hundred three million, one thousand, one hundred thirty-two".