Base | Representation |
---|---|
bin | 11011010101011100101001… |
… | …001101111100000010100011 |
3 | 120202200000201122010212111102 |
4 | 123111130221031330002203 |
5 | 111224200324000230422 |
6 | 1103404453125305015 |
7 | 34215455311430033 |
oct | 3325345115740243 |
9 | 522600648125442 |
10 | 120221121101987 |
11 | 353405447819a4 |
12 | 115977aa26516b |
13 | 5210a59482319 |
14 | 2198a3a2a98c3 |
15 | dd7361e99192 |
hex | 6d572937c0a3 |
120221121101987 has 2 divisors, whose sum is σ = 120221121101988. Its totient is φ = 120221121101986.
The previous prime is 120221121101881. The next prime is 120221121102029. The reversal of 120221121101987 is 789101121122021.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 120221121101987 - 226 = 120221053993123 is a prime.
It is a super-3 number, since 3×1202211211019873 (a number of 43 digits) contains 333 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 120221121101987.
It is not a weakly prime, because it can be changed into another prime (120221121101387) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60110560550993 + 60110560550994.
It is an arithmetic number, because the mean of its divisors is an integer number (60110560550994).
Almost surely, 2120221121101987 is an apocalyptic number.
120221121101987 is a deficient number, since it is larger than the sum of its proper divisors (1).
120221121101987 is an equidigital number, since it uses as much as digits as its factorization.
120221121101987 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8064, while the sum is 38.
The spelling of 120221121101987 in words is "one hundred twenty trillion, two hundred twenty-one billion, one hundred twenty-one million, one hundred one thousand, nine hundred eighty-seven".
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