Base | Representation |
---|---|
bin | 11011010101011100110101… |
… | …000110001111100100010011 |
3 | 120202200001020112011211121221 |
4 | 123111130311012033210103 |
5 | 111224201231011131121 |
6 | 1103404525005225511 |
7 | 34215463251510052 |
oct | 3325346506174423 |
9 | 522601215154557 |
10 | 120221320411411 |
11 | 3534063723302a |
12 | 11597844b62297 |
13 | 5210a8b8571ab |
14 | 2198a5894c399 |
15 | dd7374718b41 |
hex | 6d573518f913 |
120221320411411 has 4 divisors (see below), whose sum is σ = 120221362362024. Its totient is φ = 120221278460800.
The previous prime is 120221320411399. The next prime is 120221320411453. The reversal of 120221320411411 is 114114023122021.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-120221320411411 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (120221320411711) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16334350 + ... + 22522291.
It is an arithmetic number, because the mean of its divisors is an integer number (30055340590506).
Almost surely, 2120221320411411 is an apocalyptic number.
120221320411411 is a deficient number, since it is larger than the sum of its proper divisors (41950613).
120221320411411 is an equidigital number, since it uses as much as digits as its factorization.
120221320411411 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 41950612.
The product of its (nonzero) digits is 768, while the sum is 25.
Adding to 120221320411411 its reverse (114114023122021), we get a palindrome (234335343533432).
The spelling of 120221320411411 in words is "one hundred twenty trillion, two hundred twenty-one billion, three hundred twenty million, four hundred eleven thousand, four hundred eleven".
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