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12022402003 = 17990774051
BaseRepresentation
bin10110011001001011…
…10100101111010011
31011000212021022010021
423030211310233103
5144110213331003
65304545444311
7603632505463
oct131445645723
934025238107
1012022402003
11510a372627
1223b6340697
1311979a9351
148209adba3
154a56e82bd
hex2cc974bd3

12022402003 has 8 divisors (see below), whose sum is σ = 12103058880. Its totient is φ = 11941895400.

The previous prime is 12022401973. The next prime is 12022402009. The reversal of 12022402003 is 30020422021.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 12022402003 - 221 = 12020304851 is a prime.

It is a super-3 number, since 3×120224020033 (a number of 31 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12022402009) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 125328 + ... + 199378.

It is an arithmetic number, because the mean of its divisors is an integer number (1512882360).

Almost surely, 212022402003 is an apocalyptic number.

12022402003 is a deficient number, since it is larger than the sum of its proper divisors (80656877).

12022402003 is an equidigital number, since it uses as much as digits as its factorization.

12022402003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 75137.

The product of its (nonzero) digits is 192, while the sum is 16.

Adding to 12022402003 its reverse (30020422021), we get a palindrome (42042824024).

The spelling of 12022402003 in words is "twelve billion, twenty-two million, four hundred two thousand, three".

Divisors: 1 179 907 74051 162353 13255129 67164257 12022402003