Base | Representation |
---|---|
bin | 10110011001001011… |
… | …11110100010101001 |
3 | 1011000212100100012022 |
4 | 23030211332202221 |
5 | 144110221122103 |
6 | 5304550354225 |
7 | 603633033521 |
oct | 131445764251 |
9 | 34025310168 |
10 | 12022442153 |
11 | 510a39a807 |
12 | 23b635b975 |
13 | 11979c16c7 |
14 | 8209c0681 |
15 | 4a5705138 |
hex | 2cc97e8a9 |
12022442153 has 4 divisors (see below), whose sum is σ = 12347373060. Its totient is φ = 11697511248.
The previous prime is 12022442129. The next prime is 12022442209. The reversal of 12022442153 is 35124422021.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 9111084304 + 2911357849 = 95452^2 + 53957^2 .
It is a cyclic number.
It is not a de Polignac number, because 12022442153 - 28 = 12022441897 is a prime.
It is a Duffinian number.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (12022442123) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 162465398 + ... + 162465471.
It is an arithmetic number, because the mean of its divisors is an integer number (3086843265).
Almost surely, 212022442153 is an apocalyptic number.
It is an amenable number.
12022442153 is a deficient number, since it is larger than the sum of its proper divisors (324930907).
12022442153 is an equidigital number, since it uses as much as digits as its factorization.
12022442153 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 324930906.
The product of its (nonzero) digits is 3840, while the sum is 26.
Adding to 12022442153 its reverse (35124422021), we get a palindrome (47146864174).
The spelling of 12022442153 in words is "twelve billion, twenty-two million, four hundred forty-two thousand, one hundred fifty-three".
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