Base | Representation |
---|---|
bin | 1010111011110101100010… |
… | …1110010101001101110011 |
3 | 1120120101201122120101212110 |
4 | 2232331120232111031303 |
5 | 3033441303103031120 |
6 | 41323200430100403 |
7 | 2350432450543065 |
oct | 256753056251563 |
9 | 46511648511773 |
10 | 12023102002035 |
11 | 3915a72702973 |
12 | 14221a864a703 |
13 | 692a09943887 |
14 | 2d7cc7c5d735 |
15 | 15cb3617d2e0 |
hex | aef58b95373 |
12023102002035 has 16 divisors (see below), whose sum is σ = 19563013428480. Its totient is φ = 6303637659360.
The previous prime is 12023102002033. The next prime is 12023102002049. The reversal of 12023102002035 is 53020020132021.
It is not a de Polignac number, because 12023102002035 - 21 = 12023102002033 is a prime.
It is not an unprimeable number, because it can be changed into a prime (12023102002031) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 6792712111 + ... + 6792713880.
It is an arithmetic number, because the mean of its divisors is an integer number (1222688339280).
Almost surely, 212023102002035 is an apocalyptic number.
12023102002035 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
12023102002035 is a deficient number, since it is larger than the sum of its proper divisors (7539911426445).
12023102002035 is a wasteful number, since it uses less digits than its factorization.
12023102002035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 13585426058.
The product of its (nonzero) digits is 720, while the sum is 21.
Adding to 12023102002035 its reverse (53020020132021), we get a palindrome (65043122134056).
The spelling of 12023102002035 in words is "twelve trillion, twenty-three billion, one hundred two million, two thousand, thirty-five".
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