Base | Representation |
---|---|
bin | 11011010101100111001011… |
… | …010100000001010100001011 |
3 | 120202201002220210211211221120 |
4 | 123111213023110001110023 |
5 | 111224342004204240133 |
6 | 1103414003250010323 |
7 | 34216335466161453 |
oct | 3325471324012413 |
9 | 522632823754846 |
10 | 120232430540043 |
11 | 35345318650118 |
12 | 11599a258769a3 |
13 | 5211b3c5305c3 |
14 | 21993d02c8d63 |
15 | dd77c4cadab3 |
hex | 6d59cb50150b |
120232430540043 has 4 divisors (see below), whose sum is σ = 160309907386728. Its totient is φ = 80154953693360.
The previous prime is 120232430540029. The next prime is 120232430540051. The reversal of 120232430540043 is 340045034232021.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 120232430540043 - 218 = 120232430277899 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 120232430539986 and 120232430540013.
It is not an unprimeable number, because it can be changed into a prime (120232430540003) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20038738423338 + ... + 20038738423343.
It is an arithmetic number, because the mean of its divisors is an integer number (40077476846682).
Almost surely, 2120232430540043 is an apocalyptic number.
120232430540043 is a deficient number, since it is larger than the sum of its proper divisors (40077476846685).
120232430540043 is an equidigital number, since it uses as much as digits as its factorization.
120232430540043 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 40077476846684.
The product of its (nonzero) digits is 69120, while the sum is 33.
Adding to 120232430540043 its reverse (340045034232021), we get a palindrome (460277464772064).
The spelling of 120232430540043 in words is "one hundred twenty trillion, two hundred thirty-two billion, four hundred thirty million, five hundred forty thousand, forty-three".
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