Base | Representation |
---|---|
bin | 11011010101100111111111… |
… | …110011110110101010010011 |
3 | 120202201012012012011002210201 |
4 | 123111213333303312222103 |
5 | 111224400310143101433 |
6 | 1103414230511440031 |
7 | 34216366352415451 |
oct | 3325477763665223 |
9 | 522635165132721 |
10 | 120233311300243 |
11 | 3534572a831309 |
12 | 1159a030826017 |
13 | 5211c4cb4b89b |
14 | 21994752779d1 |
15 | dd7827289a7d |
hex | 6d59ffcf6a93 |
120233311300243 has 2 divisors, whose sum is σ = 120233311300244. Its totient is φ = 120233311300242.
The previous prime is 120233311300211. The next prime is 120233311300313. The reversal of 120233311300243 is 342003113332021.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 120233311300243 - 25 = 120233311300211 is a prime.
It is a super-2 number, since 2×1202333113002432 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (120233311300943) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (31) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60116655650121 + 60116655650122.
It is an arithmetic number, because the mean of its divisors is an integer number (60116655650122).
Almost surely, 2120233311300243 is an apocalyptic number.
120233311300243 is a deficient number, since it is larger than the sum of its proper divisors (1).
120233311300243 is an equidigital number, since it uses as much as digits as its factorization.
120233311300243 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 7776, while the sum is 28.
Adding to 120233311300243 its reverse (342003113332021), we get a palindrome (462236424632264).
The spelling of 120233311300243 in words is "one hundred twenty trillion, two hundred thirty-three billion, three hundred eleven million, three hundred thousand, two hundred forty-three".
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