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12023531553113 = 47255819820279
BaseRepresentation
bin1010111011110111001001…
…0100111100000101011001
31120120102211120211212011122
42232331302110330011121
53033443143034144423
641323311212535025
72350446214633433
oct256756224740531
946512746755148
1012023531553113
113916173121a63
1214222a8481475
13692a77930a02
142d7d28d17653
1515cb5dc2c8c8
hexaef7253c159

12023531553113 has 4 divisors (see below), whose sum is σ = 12279351373440. Its totient is φ = 11767711732788.

The previous prime is 12023531553107. The next prime is 12023531553161. The reversal of 12023531553113 is 31135513532021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 12023531553113 - 214 = 12023531536729 is a prime.

It is a super-2 number, since 2×120235315531132 (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12023531550113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 127909910093 + ... + 127909910186.

It is an arithmetic number, because the mean of its divisors is an integer number (3069837843360).

Almost surely, 212023531553113 is an apocalyptic number.

It is an amenable number.

12023531553113 is a deficient number, since it is larger than the sum of its proper divisors (255819820327).

12023531553113 is an equidigital number, since it uses as much as digits as its factorization.

12023531553113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 255819820326.

The product of its (nonzero) digits is 40500, while the sum is 35.

The spelling of 12023531553113 in words is "twelve trillion, twenty-three billion, five hundred thirty-one million, five hundred fifty-three thousand, one hundred thirteen".

Divisors: 1 47 255819820279 12023531553113