Base | Representation |
---|---|
bin | 11011010101101010000100… |
… | …010100000111100001000011 |
3 | 120202201101221010012202022211 |
4 | 123111222010110013201003 |
5 | 111224414333243203103 |
6 | 1103415235243242551 |
7 | 34216505425136323 |
oct | 3325520424074103 |
9 | 522641833182284 |
10 | 120235534350403 |
11 | 3534667067484a |
12 | 1159a551219457 |
13 | 5212215590a94 |
14 | 21996065d5283 |
15 | dd790750b36d |
hex | 6d5a84507843 |
120235534350403 has 2 divisors, whose sum is σ = 120235534350404. Its totient is φ = 120235534350402.
The previous prime is 120235534350353. The next prime is 120235534350409. The reversal of 120235534350403 is 304053435532021.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 120235534350403 - 29 = 120235534349891 is a prime.
It is not a weakly prime, because it can be changed into another prime (120235534350409) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60117767175201 + 60117767175202.
It is an arithmetic number, because the mean of its divisors is an integer number (60117767175202).
Almost surely, 2120235534350403 is an apocalyptic number.
120235534350403 is a deficient number, since it is larger than the sum of its proper divisors (1).
120235534350403 is an equidigital number, since it uses as much as digits as its factorization.
120235534350403 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 648000, while the sum is 40.
Adding to 120235534350403 its reverse (304053435532021), we get a palindrome (424288969882424).
The spelling of 120235534350403 in words is "one hundred twenty trillion, two hundred thirty-five billion, five hundred thirty-four million, three hundred fifty thousand, four hundred three".
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