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120253141541353 is a prime number
BaseRepresentation
bin11011010101111010011101…
…110010001110000111101001
3120202210002101012020201122011
4123111322131302032013221
5111230211413213310403
61103431310334355521
734221000643606462
oct3325723562160751
9522702335221564
10120253141541353
1135353086452a27
12115a1a4595bba1
135213a902c9b72
14219a3d6badd69
15dd80d8171a6d
hex6d5e9dc8e1e9

120253141541353 has 2 divisors, whose sum is σ = 120253141541354. Its totient is φ = 120253141541352.

The previous prime is 120253141541327. The next prime is 120253141541417. The reversal of 120253141541353 is 353145141352021.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 118446044757264 + 1807096784089 = 10883292^2 + 1344283^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-120253141541353 is a prime.

It is not a weakly prime, because it can be changed into another prime (120253141544353) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60126570770676 + 60126570770677.

It is an arithmetic number, because the mean of its divisors is an integer number (60126570770677).

Almost surely, 2120253141541353 is an apocalyptic number.

It is an amenable number.

120253141541353 is a deficient number, since it is larger than the sum of its proper divisors (1).

120253141541353 is an equidigital number, since it uses as much as digits as its factorization.

120253141541353 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 216000, while the sum is 40.

Adding to 120253141541353 its reverse (353145141352021), we get a palindrome (473398282893374).

The spelling of 120253141541353 in words is "one hundred twenty trillion, two hundred fifty-three billion, one hundred forty-one million, five hundred forty-one thousand, three hundred fifty-three".