Search a number
-
+
120320104313 = 831449639811
BaseRepresentation
bin111000000001110100…
…0110001011101111001
3102111120022111121001202
41300003220301131321
53432403421314223
6131135125223545
711456434004063
oct1600350613571
9374508447052
10120320104313
1147033620242
121b39ab61bb5
13b466603bc6
145b75a70733
1531e3136428
hex1c03a31779

120320104313 has 4 divisors (see below), whose sum is σ = 121769744208. Its totient is φ = 118870464420.

The previous prime is 120320104301. The next prime is 120320104343. The reversal of 120320104313 is 313401023021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-120320104313 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (120320104343) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 724819823 + ... + 724819988.

It is an arithmetic number, because the mean of its divisors is an integer number (30442436052).

Almost surely, 2120320104313 is an apocalyptic number.

It is an amenable number.

120320104313 is a deficient number, since it is larger than the sum of its proper divisors (1449639895).

120320104313 is an equidigital number, since it uses as much as digits as its factorization.

120320104313 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1449639894.

The product of its (nonzero) digits is 432, while the sum is 20.

Adding to 120320104313 its reverse (313401023021), we get a palindrome (433721127334).

The spelling of 120320104313 in words is "one hundred twenty billion, three hundred twenty million, one hundred four thousand, three hundred thirteen".

Divisors: 1 83 1449639811 120320104313