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120330110113 = 503239224871
BaseRepresentation
bin111000000010000111…
…0111100010010100001
3102111121000022221102221
41300010032330102201
53432414002010423
6131140123511041
711456615026363
oct1600416742241
9374530287387
10120330110113
11470392347a4
121b3a2388481
13b4686c82b5
145b77116d33
1531e3e60e5d
hex1c043bc4a1

120330110113 has 4 divisors (see below), whose sum is σ = 120569335488. Its totient is φ = 120090884740.

The previous prime is 120330110099. The next prime is 120330110249. The reversal of 120330110113 is 311011033021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 120330110113 - 217 = 120329979041 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (120330111113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 119611933 + ... + 119612938.

It is an arithmetic number, because the mean of its divisors is an integer number (30142333872).

Almost surely, 2120330110113 is an apocalyptic number.

It is an amenable number.

120330110113 is a deficient number, since it is larger than the sum of its proper divisors (239225375).

120330110113 is an equidigital number, since it uses as much as digits as its factorization.

120330110113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 239225374.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 120330110113 its reverse (311011033021), we get a palindrome (431341143134).

The spelling of 120330110113 in words is "one hundred twenty billion, three hundred thirty million, one hundred ten thousand, one hundred thirteen".

Divisors: 1 503 239224871 120330110113