Base | Representation |
---|---|
bin | 10110011010011111… |
… | …00101101000000001 |
3 | 1011001121212112011000 |
4 | 23031033211220001 |
5 | 144121014201040 |
6 | 5310020242213 |
7 | 604124534325 |
oct | 131517455001 |
9 | 34047775130 |
10 | 12033350145 |
11 | 5115570083 |
12 | 23b9b40369 |
13 | 119a04063b |
14 | 82221d985 |
15 | 4a665c130 |
hex | 2cd3e5a01 |
12033350145 has 32 divisors (see below), whose sum is σ = 21914403840. Its totient is φ = 6261252480.
The previous prime is 12033350141. The next prime is 12033350171. The reversal of 12033350145 is 54105333021.
12033350145 is a `hidden beast` number, since 120 + 3 + 33 + 501 + 4 + 5 = 666.
It is not a de Polignac number, because 12033350145 - 22 = 12033350141 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (27).
It is not an unprimeable number, because it can be changed into a prime (12033350141) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1081489 + ... + 1092558.
It is an arithmetic number, because the mean of its divisors is an integer number (684825120).
Almost surely, 212033350145 is an apocalyptic number.
12033350145 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
12033350145 is a deficient number, since it is larger than the sum of its proper divisors (9881053695).
12033350145 is a wasteful number, since it uses less digits than its factorization.
12033350145 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2174102 (or 2174096 counting only the distinct ones).
The product of its (nonzero) digits is 5400, while the sum is 27.
Adding to 12033350145 its reverse (54105333021), we get a palindrome (66138683166).
The spelling of 12033350145 in words is "twelve billion, thirty-three million, three hundred fifty thousand, one hundred forty-five".
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