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120343131523 is a prime number
BaseRepresentation
bin111000000010100000…
…0100111010110000011
3102111121220211111110101
41300011000213112003
53432430320202043
6131141310543231
711460133511566
oct1600500472603
9374556744411
10120343131523
114704561899a
121b3a6807b17
13b46b307184
145b78b464dd
1531e518424d
hex1c05027583

120343131523 has 2 divisors, whose sum is σ = 120343131524. Its totient is φ = 120343131522.

The previous prime is 120343131421. The next prime is 120343131547. The reversal of 120343131523 is 325131343021.

It is a strong prime.

It is an emirp because it is prime and its reverse (325131343021) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-120343131523 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 120343131491 and 120343131500.

It is not a weakly prime, because it can be changed into another prime (120343111523) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60171565761 + 60171565762.

It is an arithmetic number, because the mean of its divisors is an integer number (60171565762).

Almost surely, 2120343131523 is an apocalyptic number.

120343131523 is a deficient number, since it is larger than the sum of its proper divisors (1).

120343131523 is an equidigital number, since it uses as much as digits as its factorization.

120343131523 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6480, while the sum is 28.

Adding to 120343131523 its reverse (325131343021), we get a palindrome (445474474544).

The spelling of 120343131523 in words is "one hundred twenty billion, three hundred forty-three million, one hundred thirty-one thousand, five hundred twenty-three".