Base | Representation |
---|---|
bin | 1010111100011111101001… |
… | …0101101111111001000011 |
3 | 1120121110220021010222010222 |
4 | 2233013322111233321003 |
5 | 3034132424232320113 |
6 | 41332310102213255 |
7 | 2351312510053664 |
oct | 257077225577103 |
9 | 46543807128128 |
10 | 12034403401283 |
11 | 391a841a9044a |
12 | 142442142422b |
13 | 693abb138b73 |
14 | 2d867ab8936b |
15 | 15d098405e08 |
hex | af1fa56fe43 |
12034403401283 has 2 divisors, whose sum is σ = 12034403401284. Its totient is φ = 12034403401282.
The previous prime is 12034403401217. The next prime is 12034403401303. The reversal of 12034403401283 is 38210430443021.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12034403401283 - 236 = 11965683924547 is a prime.
It is not a weakly prime, because it can be changed into another prime (12034403401213) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6017201700641 + 6017201700642.
It is an arithmetic number, because the mean of its divisors is an integer number (6017201700642).
Almost surely, 212034403401283 is an apocalyptic number.
12034403401283 is a deficient number, since it is larger than the sum of its proper divisors (1).
12034403401283 is an equidigital number, since it uses as much as digits as its factorization.
12034403401283 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 55296, while the sum is 35.
The spelling of 12034403401283 in words is "twelve trillion, thirty-four billion, four hundred three million, four hundred one thousand, two hundred eighty-three".
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