Base | Representation |
---|---|
bin | 1010111100100010010111… |
… | …1101011011101000100001 |
3 | 1120121112210021012102200010 |
4 | 2233020211331123220201 |
5 | 3034140424104134403 |
6 | 41332510443515133 |
7 | 2351336604335643 |
oct | 257104575335041 |
9 | 46545707172603 |
10 | 12035135224353 |
11 | 39200880959aa |
12 | 14245a6528aa9 |
13 | 693ba693ac77 |
14 | 2d870a048893 |
15 | 15d0dc7b2603 |
hex | af225f5ba21 |
12035135224353 has 32 divisors (see below), whose sum is σ = 16425196381440. Its totient is φ = 7835679221760.
The previous prime is 12035135224339. The next prime is 12035135224381. The reversal of 12035135224353 is 35342253153021.
It is not a de Polignac number, because 12035135224353 - 221 = 12035133127201 is a prime.
It is not an unprimeable number, because it can be changed into a prime (12035135224393) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 82427868 + ... + 82573746.
It is an arithmetic number, because the mean of its divisors is an integer number (513287386920).
Almost surely, 212035135224353 is an apocalyptic number.
It is an amenable number.
12035135224353 is a deficient number, since it is larger than the sum of its proper divisors (4390061157087).
12035135224353 is a wasteful number, since it uses less digits than its factorization.
12035135224353 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 148329.
The product of its (nonzero) digits is 324000, while the sum is 39.
Adding to 12035135224353 its reverse (35342253153021), we get a palindrome (47377388377374).
The spelling of 12035135224353 in words is "twelve trillion, thirty-five billion, one hundred thirty-five million, two hundred twenty-four thousand, three hundred fifty-three".
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