1204011413233 has 2 divisors, whose sum is σ = 1204011413234. Its totient is φ = 1204011413232.

The previous prime is 1204011413203. The next prime is 1204011413237. The reversal of 1204011413233 is 3323141104021.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 709961278464 + 494050134769 = 842592^2 + 702887^2 .

It is a cyclic number.

It is not a de Polignac number, because 1204011413233 - 2⁵ = 1204011413201 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1204011413198 and 1204011413207.

It is not a weakly prime, because it can be changed into another prime (1204011413237) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 602005706616 + 602005706617.

It is an arithmetic number, because the mean of its divisors is an integer number (602005706617).

Almost surely, 2^{1204011413233} is an apocalyptic number.

It is an amenable number.

1204011413233 is a deficient number, since it is larger than the sum of its proper divisors (1).

1204011413233 is an equidigital number, since it uses as much as digits as its factorization.

1204011413233 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 1204011413233 its reverse (3323141104021), we get a palindrome (4527152517254).

The spelling of 1204011413233 in words is "one trillion, two hundred four billion, eleven million, four hundred thirteen thousand, two hundred thirty-three".