12040420043 has 4 divisors (see below), whose sum is σ = 12040794480. Its totient is φ = 12040045608.

The previous prime is 12040420019. The next prime is 12040420141. The reversal of 12040420043 is 34002404021.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 12040420043 - 2³² = 7745452747 is a prime.

It is a super-2 number, since 2×12040420043² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12040419997 and 12040420024.

It is not an unprimeable number, because it can be changed into a prime (12040429043) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 133928 + ... + 204981.

It is an arithmetic number, because the mean of its divisors is an integer number (3010198620).

Almost surely, 2^12040420043 is an apocalyptic number.

12040420043 is a deficient number, since it is larger than the sum of its proper divisors (374437).

12040420043 is an equidigital number, since it uses as much as digits as its factorization.

12040420043 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 374436.

The product of its (nonzero) digits is 768, while the sum is 20.

Adding to 12040420043 its reverse (34002404021), we get a palindrome (46042824064).

The spelling of 12040420043 in words is "twelve billion, forty million, four hundred twenty thousand, forty-three".