Base | Representation |
---|---|
bin | 10001100001011001111… |
… | …101011001101100011011 |
3 | 11021002222210210100002021 |
4 | 101201121331121230123 |
5 | 124211444112024011 |
6 | 2321053404115311 |
7 | 152664503033551 |
oct | 21413175315433 |
9 | 4232883710067 |
10 | 1204100111131 |
11 | 424724138295 |
12 | 175442835b37 |
13 | 89713b8b678 |
14 | 423c8c9bbd1 |
15 | 214c4b38471 |
hex | 11859f59b1b |
1204100111131 has 2 divisors, whose sum is σ = 1204100111132. Its totient is φ = 1204100111130.
The previous prime is 1204100111119. The next prime is 1204100111153. The reversal of 1204100111131 is 1311110014021.
It is a weak prime.
It is an emirp because it is prime and its reverse (1311110014021) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1204100111131 - 225 = 1204066556699 is a prime.
It is a super-2 number, since 2×12041001111312 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1204100111101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 602050055565 + 602050055566.
It is an arithmetic number, because the mean of its divisors is an integer number (602050055566).
Almost surely, 21204100111131 is an apocalyptic number.
1204100111131 is a deficient number, since it is larger than the sum of its proper divisors (1).
1204100111131 is an equidigital number, since it uses as much as digits as its factorization.
1204100111131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24, while the sum is 16.
Adding to 1204100111131 its reverse (1311110014021), we get a palindrome (2515210125152).
The spelling of 1204100111131 in words is "one trillion, two hundred four billion, one hundred million, one hundred eleven thousand, one hundred thirty-one".
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