Base | Representation |
---|---|
bin | 1010111100111000101000… |
… | …1010001000111001000001 |
3 | 1120122010012202010200222012 |
4 | 2233032022022020321001 |
5 | 3034240143434304403 |
6 | 41335335442422305 |
7 | 2351640650560532 |
oct | 257161212107101 |
9 | 46563182120865 |
10 | 12041111244353 |
11 | 3922674428204 |
12 | 1425793961995 |
13 | 694619a5bb89 |
14 | 2d8b159b4689 |
15 | 15d33c25eed8 |
hex | af38a288e41 |
12041111244353 has 2 divisors, whose sum is σ = 12041111244354. Its totient is φ = 12041111244352.
The previous prime is 12041111244179. The next prime is 12041111244367. The reversal of 12041111244353 is 35344211114021.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 9400460244289 + 2640651000064 = 3066017^2 + 1625008^2 .
It is a cyclic number.
It is not a de Polignac number, because 12041111244353 - 214 = 12041111227969 is a prime.
It is not a weakly prime, because it can be changed into another prime (12041111244053) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6020555622176 + 6020555622177.
It is an arithmetic number, because the mean of its divisors is an integer number (6020555622177).
Almost surely, 212041111244353 is an apocalyptic number.
It is an amenable number.
12041111244353 is a deficient number, since it is larger than the sum of its proper divisors (1).
12041111244353 is an equidigital number, since it uses as much as digits as its factorization.
12041111244353 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 11520, while the sum is 32.
Adding to 12041111244353 its reverse (35344211114021), we get a palindrome (47385322358374).
The spelling of 12041111244353 in words is "twelve trillion, forty-one billion, one hundred eleven million, two hundred forty-four thousand, three hundred fifty-three".
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